1/(x+8)^2=0 - solution

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Solution for 1/(x+8)^2=0 equation:

D( x )

(x+8)^2 = 0

(x+8)^2 = 0

(x+8)^2 = 0

x+8 = 0 // - 8

x = -8

x in (-oo:-8) U (-8:+oo)

1/((x+8)^2) = 0

x belongs to the empty set

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